IQ Test, Logic test, Fun :)

Started by Ggs`
13/02/2011 23:59
Page 4 of 7
bp04/05/2011 14:04

I have a headache ..
I don't know all about that

Ggs`09/05/2011 16:27

Originally posted by Ggs`
we have 2 Bottle's with tablets(2 in every botl), In first bottle - tablets A, in second - tablets B. Every day we need to take 2 batlets, A+B or other way we'll die. Suddenly we see that our tablets fell on the table. so we have 3 tabl on the table and one in the botl. How to eat those drugs and dont die
Hope I explained it clear :)

ok, I guess this problem too hard for you :(
it simple as hel, you just need to eat half of every tablets at first day, and other halfs in next one :P

____

So anyone still interested in this topic or I should just close it?

balling09/05/2011 19:44

Originally posted by Ggs`
Originally posted by Ggs`
we have 2 Bottle's with tablets(2 in every botl), In first bottle - tablets A, in second - tablets B. Every day we need to take 2 batlets, A+B or other way we'll die. Suddenly we see that our tablets fell on the table. so we have 3 tabl on the table and one in the botl. How to eat those drugs and dont die
Hope I explained it clear :)

ok, I guess this problem too hard for you :(
it simple as hel, you just need to eat half of every tablets at first day, and other halfs in next one :P

____

So anyone still interested in this topic or I should just close it?


I really like it :) The problem you posted just didnt make any sense at all to me..

zgooh10/05/2011 00:30

Gaaaah ! I imagine them as "gellules" (fr), I now have like 4 pieces of paper full of possibilities ! x)

Yeah, I would like some more, friend :)

Ggs`10/05/2011 01:17(edited 10/05/2011 01:17)

hehe :)

here another one:

train in tunnel

we have tunnel (4 km). Guy goin throw this tonnel and after he did 1/4(1km) of this tunnel he hear train signal behind. If he come back - train kill him at the inlet, if he go forward - train kill him at the end of tunnel.

question : train speed please :)

good luck brain maniacs

feel free to request me tips

remake10/05/2011 06:48

Gonna try that one after getting back from school.

kQbmigrecord holder10/05/2011 08:20

Originally posted by Ggs`
hehe :)

here another one:

train in tunnel

we have tunnel (4 km). Guy goin throw this tonnel and after he did 1/4(1km) of this tunnel he hear train signal behind. If he come back - train kill him at the inlet, if he go forward - train kill him at the end of tunnel.

question : train speed please :)

good luck brain maniacs

feel free to request me tips


Twice the speed of the guy.

Ggs`10/05/2011 10:12(edited 10/05/2011 10:37)

Originally posted by NAPZ
Originally posted by Ggs`
hehe :)

here another one:

train in tunnel

we have tunnel (4 km). Guy goin throw this tonnel and after he did 1/4(1km) of this tunnel he hear train signal behind. If he come back - train kill him at the inlet, if he go forward - train kill him at the end of tunnel.

question : train speed please :)

good luck brain maniacs

feel free to request me tips


Twice the speed of the guy.

how did you calculate it, more precisely please :)

Nukk10/05/2011 11:05

google know result of it

InfinityBG16/03/2013 11:57

i want this thread alive again, cmon guys

znx16/03/2013 15:50

Originally posted by Ggs`
Originally posted by NAPZ
Originally posted by Ggs`
hehe :)

here another one:

train in tunnel

we have tunnel (4 km). Guy goin throw this tonnel and after he did 1/4(1km) of this tunnel he hear train signal behind. If he come back - train kill him at the inlet, if he go forward - train kill him at the end of tunnel.

question : train speed please :)

good luck brain maniacs

feel free to request me tips


Twice the speed of the guy.

how did you calculate it, more precisely please :)


I dont know if this is what you meant but this is how I understood the question.

Since the man and the train are at 1 km distance at the time, and if the man walks back he will die at the station. Meaning, the train will start moving when he is just about to walk 1 KM.

Now if he moved forward, He would be at 2 kms and he would need to walk 2kms more to reach the exit. In this case the train has to travel 4 kms (Since first 1 km of walking is neglected) and man has to travel 2 kms at his speed. It is said he will die when he reaches the end. i,e, Train speed = 2x mans speed.

k a f f e e19/03/2013 21:24

of 4 bags with allegedly real diamonds one is filled with fake diamonds. a real diamond weights 1gram, a fake one 2 gram.

you get the 4 bags of diamonds from a weird looking fella. you have a scale that tells you the exact weight of whatever you put into the scale pan. how can you find out which one is the bag that contains fake diamonds if you are only allowed to weigh 1 time

koukouz mapperrecord holder19/03/2013 22:31

You have bag 1, 2, 3 and 4. You take none from bag 1, 1 from bag 2, 2 from bag 3 and 3 from bag 4.

If it weighs 6g, it is bag 1.
If it weighs 7g, it is bag 2.
If it weighs 8g, it is bag 3.
If it weighs 9g, it is bag 4.

CamelCloudrecord holder19/03/2013 23:26

i have 126 iq

k a f f e e20/03/2013 00:16

Originally posted by koukouz
You have bag 1, 2, 3 and 4. You take none from bag 1, 1 from bag 2, 2 from bag 3 and 3 from bag 4.

If it weighs 6g, it is bag 1.
If it weighs 7g, it is bag 2.
If it weighs 8g, it is bag 3.
If it weighs 9g, it is bag 4.


correct. lets get a little more difficult:

#2

there are 23 prisoners in a prison and 2 flip switches on a wall in the yard. the director of the prison will send each one of them atleast one time to the yard, where the prisoner will have to turn one of the two switches on or off exactly one time before he will be send back. however, he can send the same prisoner to the yard an arbitrary number of times, but he will send everyone atleast 1 time.

when one of the prisoners tells the director, if each one of the prisoners was on the yard atleast 1 time, everybody will get kebap, strippers and beer.

all prisoners can agree on a strategy about what to do. afterwards they wont see each other again until one of them solved the riddle (seperated cells)

what strategy would work?


btw, the switches look like this: http://img.alibaba.com/photo/565948009/Crystal_glass_panel_1gang_2way_key_board_light_switch.jpg and they dont have any function except that you can turn em "on" or "off". when the test starts, both switches are set to "off"

finzer20/03/2013 01:18

awh i already know this one :/. will post the solution later if none finds it. great riddle

k a f f e e20/03/2013 12:13

Originally posted by finzEr
awh i already know this one :/. will post the solution later if none finds it. great riddle


just post the solution, i have a few more coming hehe.
actually i have never seen a real solution to this because my friend presented it to me as something he couldnt solve. i came up with a strategy that should defenitly work, in the web i only found false solutions

koukouz mapperrecord holder20/03/2013 13:07(edited 20/03/2013 13:09)

Is there any consequence if a prisoner tells the director but it's wrong? If not, then they can simply tell him every time they come back from the yard. Eventually one will be right.

Else they can mark the wall with a blood dot or something when it's the first time they go in the yard, the guy who sees 22 dots and comes for the first time is the last.

Anyway what do these switches activate, if it has any relevance?
Also, can the prisoners hear if anyone came into the yard?

znx20/03/2013 14:33

Yeah, if they could tell him even if they were wrong, everyone can tell him.

finzer20/03/2013 16:57(edited 20/03/2013 17:18)

OK, i’ll try to be as clear as possible. First of all, one prisoner among the 23 little rats is going to be the ‘counter’ (gotta see this as a sort of algorithm). He is the only one that can tell the director when he thinks everyone’s been on the yard at least once. One other important thing is to differentiate the two switches: let’s call one A and one B.

The ‘counter’ switches the A button to OFF when it’s ON. Otherwise he switches the B button (B’s position ain’t important) when A is OFF. When he switches the A to OFF, he increases the counter by one. The 22 other fellows must switch A button to ON when it’s OFF. Otherwise they switch B if A is already on ON position. They also have to remember if they’ve already switched the A button previously: if they have, they just toggle the B button). Each time the ‘counter’ switches the A button to OFF, he knows that one prisoner previously toggled it to ON before. When he finally reaches “22” (the ‘counter’ obviously knows he’s been outside too) counters, he can tell the director and everyone gets kebap, beers and strippers… hopefully.

im sure its not the best solution though...
it works only if everyone goes outside a lot of time (and not only once). it will also take forever: They have to wait for the counter to switch A to OFF since he is the only one allowed to. So.. sometimes, if a random prisoner goes outside and if the A button is already ON, he will toggle B and it will not be counted by the counter… so yeah weak solution :<

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